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Tuesday, 22 July 2025

Simple and Compound Microscope Class 12 Derivation

Today, we will learn about the simple and compound microscopes, which are related to Class 12 physics.

Simple Microscope


simple microscope consists of a convex lens with a short focal length.  It is an optical device used to obtain magnification of small objects of better clarity of vision.

Simple Microscope
Simple Microscope


Principal

To obtain a larger image of the object, the object is placed between the focus and the pole. This gives a large virtual, and erect image of the object.


Diagram of A Simple Microscope

Simple Microscope Ray Diagram
Simple Microscope Ray Diagram



Magnification


Magnifying Power: Magnifying power of a microscope is defined as the ratio of the angle subtended by the final image at the eye and the angle subtended by the extended object placed at least the distance of distinct vision.


Linear Magnification

Linear magnification refers to the ratio of image length to object length measured in planes that are perpendicular to the optical axis.

A negative value of linear magnification denotes an inverted image.


`M = \frac{\beta}{\alpha}`


`M = \frac{tan\beta}{tan\alpha}`     {For small angle}


`M = \frac{(\frac{AB}{OB})}{(\frac{AB}{OB'})}`


`M = \frac {AB}{OB} \times \frac {OB'}{AB}`


`M = \frac {OB'}{OB}`


`M = \frac {- D}{- u}`


`M = \frac { D }{ u }`         ....... eq. 1


Case I 


When an image is formed at least the distance of the distinct vision


Lens formula


`\frac{1}{f} = \frac{1}{v} - \frac{1}{u}`


Here


    u = - u       and         v = - D


`\frac {1}{f} = \frac{1}{- D} - \frac {1}{- u}`


`\frac {1}{f} = \frac{1}{u} - \frac {1}{D}`


On multiplying both sides by D


`\frac {D}{f} = \frac{D}{u} - \frac {D}{D}`


`\frac {D}{f} = M - 1`      {`\because \frac {D}{u} = M`}


` M = 1 +\frac {D}{f}`         ....... eq. 2


This is the maximum magnifying power


Case II


When the image is obtained at infinity


When the object is placed at the point of focus, the image is obtained at infinity. 


Thus  u = f


from equation  1


`M = \frac { D }{ f  }`


This is the minimum magnifying power


Use of a Simple Microscope


  • An astrologer uses a simple microscope to see the lines of the palm. (Palmists generally use a magnifying glass while seeing palm lines.)
  • In the laboratory of science, a microscope is used to obtain the readings of the vernier caliper, screw gauge, etc.
  • The parts of a wristwatch are very small, the watchmaker uses a simple microscope to see them.

Compound Microscope


 A compound microscope is an optical instrument with the help of which we can see very fine objects magnified. (Compound microscope: It is an optical device used to see a highly magnified image of tiny objects)


Construction


In this, there is a convex lens of short focal length and small aperture, which is placed towards the object; it is called the object lens or field lens. The second convex lens is of larger focal length and large aperture, and it is placed towards the eye; it is called the eye lens.


Both these lenses are arranged on the sides of a metal tube, the distance between these lenses can be increased or decreased by a wheel arrangement.


Adjustment and Formation of Image

In the adjustment process, the eye lens or eye pieces are adjusted first. For this, eye eyepiece is moved forward or backward up to such an extent that the cross wire should be seen clearly. 


Now the object is placed in front of the field lens, and it is moved to adjust in such a way that the clear image of the object is seen. In this situation inverted larger and virtual image of the object forms on the cross wire.


Compound Microscope
Compound Microscope


 AB is a small object, and its inverted, real, and larger image A'B' is formed by the objective lens. This image acts as a virtual object for the eye lens; therefore, it is moved forward or backward such that the image A'B' may lie within the focal length `f_e` of the eyepiece. 


The image A'B' acts as an object for the eyepiece, which essentially acts like a simple microscope. The eyepiece forms a virtual and magnified final image A'' B'' of the object clearly, and the final image is inverted to the object AB.


Magnifying Power


`M = \frac {\beta}{\alpha}`


`M = \frac {tan\beta}{tan\alpha}`


`M = \frac {\frac{A'B'}{EB'}}{\frac{AB}{EB}}`


`M = \frac{A'B'}{EB'}\times\frac{EB}{AB}`


`M = \frac{A'B'}{AB}\times\frac{EB}{EB'}`


`M = \frac{OB'}{OB}\times\frac{EB}{EB'}``[\because \frac{A'B'}{AB}=\frac{OB'}{OB}]`


`M = \frac{v_o}{- u_o}\times\frac{- D}{-u_e}`


`M = - \frac{v_o}{ u_o}\times\frac{D}{u_e}`      .....eq(1)


`M = m_o  m_e`                                             ........(2)


Case I


If the final image formed at least a distance of distinct vision


then  `v_e = - D`


lens formula


`\frac{1}{f}=\frac{1}{v} - \frac{1}{u}`


`\frac{1}{f_e}=\frac{1}{-D} - \frac{1}{- u_e}`


`\frac{1}{f_e}=\frac{1}{-D} + \frac{1}{u_e}`


`\frac{1}{u_e}=\frac{1}{D} + \frac{1}{f_e}`


Multiply by D on both sides


`\frac{D}{u_e}=\frac{D}{D} + \frac{D}{f_e}`


`\frac{D}{u_e}= 1 + \frac{D}{f_e}`


From eq (1)


`M = - \frac{v_o}{ u_o} (1 + \frac{D}{f_e})`     ....eq(3)


Case II


If the final image formed at infinity


In this condition, `u_e = f_e`


from  eq(1)


`M = - \frac{v_o}{ u_o}\times\frac{D}{f_e}`      ....(4)


If object AB is very close to the first focus of the objective lens, then `u_o=f_o`


If A'B' is very near to the eye lens, then `v_o = L`= the tubelength of the microscope


From eq(3)


`M = - \frac{L}{ f_o} (1 + \frac{D}{f_e})`


Important Questions based on Compound Microscope


 Q1.The correct statement is:
(1) The intermediate image in a compound microscope is real, erect, and magnified
(2) The intermediate image in a compound microscope is real, inverted, but diminished
(3) The intermediate image in a compound microscope is virtual, erect, and magnified
(4) The intermediate image in a compound microscope is real, inverted, and magnified

Ans:

(4) The intermediate image in a compound microscope is real, inverted, and magnified


 Q2. In case of a compound microscope, the image formed by the objective lens is:
(1) Virtual, erect, and diminished
(2) Real, erect, and magnified
(3) Virtual, inverted, and enlarged
(4) Real, inverted, and enlarged

Ans:

(4) Real, inverted, and enlarged


Q3.The magnification of a compound microscope for the final image at the least distance of distinct vision is 90. The magnification of the objective lens is 15. The value of the focal length of the eyepiece will be:
(1) 5 cm
(2) 6 cm
(3) 1/6 cm
(4) 12

Ans:

(1) 5 cm


Q4.If the focal length of the objective lens is increased, then the magnifying power of:
(1) The microscope will increase, but the telescope will decrease
(2) A microscope and a telescope both will increase
(3) The microscope and telescope both will decrease
(4) The microscope will decrease, but that of the telescope will increase

Ans:

(4) The microscope will decrease, but that of the telescope will increase



 Q5. microscope has an objective of focal length 1.5 cm and an eyepiece of focal length 2.5 cm. If the distance between the objective and eyepiece of focal length 25 cm, what is the approximate value of magnification produced for a relaxed eye?
(1) 75
(2) 110
(3) 140
(4) 25

Ans:

(3) 140


Q6. The focal length of the objective lens and the eye lens is 4mm and 25 mm, respectively, in a compound microscope. The distance between the objective and the eyepiece lens is 16 cm. Find its magnifying power for a relaxed eye position:
(1) 32.75
(2) 327.5
(3) 0.3275
(4) None of the above

Ans:

(2) 327.5


Q7.In a compound microscope, the magnification is 95, the distance of the object from the objective lens is 1/3.8 cm, and the focal length of the objective is 1/4 cm. What is the magnification of the eyepiece when the final image is formed at the least distance of distinct vision?
(1) 5
(2) 10
(3) 100
(4) None of the above

Ans:

(1) 5


Q8.The magnification power of a compound microscope does not depend upon
(1) The focal length and aperture of the eye lens 
(2) The apertures of the objective lens 
(3) Tube length of the microscope 
(4) None of the above

Ans:

(2) The apertures of the objective lens

Q9.Which among the following microscopes uses light as the source of illumination?
(1) Stereomicroscope
(2) Electron microscope
(3) SEM
(4) TEM

Ans:

(1) Stereomicroscope


Q10.Which of the following microscopes is best suited for observing live specimens without staining?
(1) Compound microscope
(2) Phase contrast microscope
(3) SEM
(4) TEM

Ans:

(2) Phase contrast microscope


Q11.If you want to assess the mass of the cell wall of bacteria, which microscope is best suited for that?
(1) Stereomicroscope
(2) Confocal microscope
(3) Interference microscope
(4) Fluorescence microscope

Ans:

(3) Interference microscope


Question for practice


(1) Draw the labelled ray diagram for the formation of the image by a compound microscope. Derive an expression for its total magnification (or magnifying power) when the final image is formed at the near point.

(2) Why must both the objective and eyepiece of a compound microscope have short focal lengths?

(3)Draw a ray diagram showing the image formation by a compound microscope. Hence, obtain the expression for the total magnification when the image is formed at infinity. 





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